Primary 5 Math: Rate Practice
Real Primary 5 Math questions on Rate, pulled directly from the Olibits question bank — the same questions a child would actually see, not separately written for this page.
MOE strand: Number and Algebra
Curriculum alignment
Mathematics Syllabus, Primary One to Six (MOE, 2021 syllabus)
Taught across P1–P6.
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Real Rate practice questions
Which of these describes a 'rate'?
The total number of pages a printer has printed so far
The colour of the printer
The size of a page
The number of pages a printer prints per minute ✓
A rate compares two different quantities, such as pages produced per minute.
Which is a better buy: 5 kg of rice for $8, or 8 kg of the same rice for $12?
Cannot compare
5 kg for $8
8 kg for $12 (that's $1.50 per kg vs $1.60 per kg) ✓
They cost the same per kg
5 kg for $8 = $1.60 per kg. 8 kg for $12 = $1.50 per kg. Since $1.50 < $1.60, the 8 kg pack is the better buy.
Wei Ling compares two printers: Printer A makes 300 pages in 5 minutes; Printer B makes 500 pages in 10 minutes. She says Printer A must be faster 'because it produces fewer total pages in less total time, and less time sounds faster.' Is Printer A actually faster, and why?
Yes - comparing pages per minute, A makes 60 pages/min vs B's 50 pages/min, so A is faster, but not for the reason Wei Ling gave ✓
They are equally fast
Cannot be determined without knowing the page size
No, Printer B is faster
Compare rates, not raw totals: A's rate = 300 ÷ 5 = 60 pages/min; B's rate = 500 ÷ 10 = 50 pages/min. A is indeed faster, but the correct reasoning is comparing pages produced per minute, not simply noting the smaller total time.
Which method correctly finds the cost of 7 kg of sugar if 4 kg costs $6.00?
Find the cost per kg first ($6.00 ÷ 4 = $1.50), then multiply by 7 ($1.50 × 7 = $10.50) ✓
Divide $6.00 by 7 to get about $0.86
Add 3 kg worth to $6.00 without finding the rate first
Multiply $6.00 by 7 directly to get $42.00
Since 7 kg is not a simple multiple of 4 kg, the correct method is to first find the rate (cost per kg = $6.00 ÷ 4 = $1.50), then multiply by the new quantity (7 kg): $1.50 × 7 = $10.50.